121x^2+1100x-9810=0

Solution for 121x^2+1100x-9810=0 equation:

121x^2+1100x-9810=0

a = 121; b = 1100; c = -9810;
Δ = b2-4ac
Δ = 11002-4·121·(-9810)
Δ = 5958040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5958040}=\sqrt{484*12310}=\sqrt{484}*\sqrt{12310}=22\sqrt{12310}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1100)-22\sqrt{12310}}{2*121}=\frac{-1100-22\sqrt{12310}}{242}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1100)+22\sqrt{12310}}{2*121}=\frac{-1100+22\sqrt{12310}}{242}
$